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1. After a task is completed, time is set to start the next communication task. The time here is different in principle. This method is the most flexible, but it has a large program size.
2. At the same timing, set different communication task control bits at different times=1. The advantage of this approach is its simple logic, while the disadvantage is that encountering a timeout may result in task loss, and the program size is also large.
3. Bit timing moves left (right), with small program size and simplicity. The disadvantage is that encountering a timeout may result in task loss. In fact, when there are many tasks (>30), the continuous method is not much different from the first method mentioned above. This is an accounting matter.
Sending and receiving messages are generally calculated in bytes, with start and stop bits added to each byte, usually 10 bits,
When the stop bit is two bits, each byte is 11 bits, plus one check bit, up to a maximum of 12 bits.
The length of the standard Modbus read data transmission message is 8 bytes, and the length of the response message varies with the read data
How much change. The general rule is 5+N, so the total number of bytes sent and received is 13+N, with a minimum value of 14.
Minimum number of digits=14 ¡Ñ 10=140 bits, or=14 ¡Ñ 12=168 digits.
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